网上找的经测试靠谱的,修改了若不是中文依然显示出来而不是返回空。考虑如果不是图省事还是写在代码里比较好吧??

create function [dbo].[fun_getPY](@str nvarchar(4000)) 
returns nvarchar(4000) 
as 
begin 
declare @word nvarchar(1),@PY nvarchar(4000) 
set @PY=''
set @str = ltrim(rtrim(@str)) 
while len(@str)>0 
begin 
set @word=left(@str,1) 

set @PY=@PY+ltrim((case when unicode(@word) between 19968 and 19968+20901 
then (select top 1 PY from ( 
select 'A' as PY,N'驁' as word 
union all select 'B',N'簿' 
union all select 'C',N'錯' 
union all select 'D',N'鵽' 
union all select 'E',N'樲' 
union all select 'F',N'鰒' 
union all select 'G',N'腂' 
union all select 'H',N'夻' 
union all select 'J',N'攈' 
union all select 'K',N'穒' 
union all select 'L',N'鱳' 
union all select 'M',N'旀' 
union all select 'N',N'桛' 
union all select 'O',N'漚' 
union all select 'P',N'曝' 
union all select 'Q',N'囕' 
union all select 'R',N'鶸' 
union all select 'S',N'蜶' 
union all select 'T',N'籜' 
union all select 'W',N'鶩' 
union all select 'X',N'鑂' 
union all select 'Y',N'韻' 
union all select 'Z',N'咗' 
) T 
where word>=@word collate Chinese_PRC_CS_AS_KS_WS
order by PY ASC)
when unicode(@word) between 8544 and 8552  --希腊字母1-9
then  nchar(unicode(@word)-8495)
when unicode(@word) = 8553  --希腊字母10
then '0'
when  unicode(@word) between 48 and 57   --数字0-9
then @word 
when  unicode(@word) between 65296 and 65305   --全角数字0-9
then nchar(unicode(@word)-65248) 
when  unicode(upper(@word)) between 65 and 90   --字母a-z和A-Z
then upper(@word) 
when  unicode(upper(@word)) between 65313 and 65338  --全角字母a-z和A-Z
then nchar(unicode(upper(@word))-65248)
else @word end))   --如果非汉字字符或非字母、数字、希腊字母、全角字母、全角数字,返回原字符 
set @str = substring(@str,2,len(@str)-1)
end 
return @PY 
end 

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